MATHS

Asked by BasmaPythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ adjacent => tan(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ hypotenuse => sin(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.

Pythagorean theorem Let angle xyz => A So tan(A) = opposite/ hypotenuse => sin(A) = 15/6 Therefore A = tan^-1(15/6) => 68.19863 So angle xyz = 68 degrees. Hope this helps Also You can book a lesson for further understanding.